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True... also this wont work if the qn said give the list of all contacts intead of just the count... We can probably still use this algorithm by using an ArrayList instead of a Count as the HashMap value, but that would increase the size even more...
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True... also this wont work if the qn said give the list of all contacts intead of just the count... We can probably still use this algorithm by using an ArrayList instead of a Count as the HashMap value, but that would increase the size even more...