We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
we can reduce number of sub queries here.
my version for above query :
select (salarymonths)earning,count() from employee where (salarymonths)=(select max(salarymonths) earning from employee) group by (salarymonths);
Cookie support is required to access HackerRank
Seems like cookies are disabled on this browser, please enable them to open this website
Top Earners
You are viewing a single comment's thread. Return to all comments →
we can reduce number of sub queries here. my version for above query : select (salarymonths)earning,count() from employee where (salarymonths)=(select max(salarymonths) earning from employee) group by (salarymonths);