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Here's an oracle solution without group by and is generalized incase the question asks for the nth maximum (where Rank = n).
SELECT AVG(EARNINGS), COUNT(*) FROM(
SELECT MONTHS*SALARY AS EARNINGS, RANK() over (order by MONTHS * SALARY DESC) as RANK FROM EMPLOYEE
)
where RANK = 1
;
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Here's an oracle solution without group by and is generalized incase the question asks for the nth maximum (where Rank = n). SELECT AVG(EARNINGS), COUNT(*) FROM( SELECT MONTHS*SALARY AS EARNINGS, RANK() over (order by MONTHS * SALARY DESC) as RANK FROM EMPLOYEE ) where RANK = 1 ;