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My code takes advantage of the constraints. Straight O(n).
staticintequalizeArray(int[]arr){intmax=0;int[]x=newint[100];//takes advantage of the fact that the values can be used to represent their index counterpartfor(inti=0;i<arr.length;i++)max=Math.max(max,++x[arr[i]-1]);returnarr.length-max;}
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Equalize the Array
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My code takes advantage of the constraints. Straight O(n).