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in second case :0 2 5 3 in this case x1=0,x2=5,v1=2,v2=3 so (x1 - x2) % (v2 - v1) == 0 as -5%1==0, so this is not correct
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Number Line Jumps
You are viewing a single comment's thread. Return to all comments →
in second case :0 2 5 3 in this case x1=0,x2=5,v1=2,v2=3 so (x1 - x2) % (v2 - v1) == 0 as -5%1==0, so this is not correct