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optimal solution is: if( ( x1 < x2 && v1 > v2 ) || ( x1 > x2 && v1 < v2 ) ) { if( abs(x1-x2)%abs(v1-v2) == 0) return "YES"; } return "NO";
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Number Line Jumps
You are viewing a single comment's thread. Return to all comments →
optimal solution is: if( ( x1 < x2 && v1 > v2 ) || ( x1 > x2 && v1 < v2 ) ) { if( abs(x1-x2)%abs(v1-v2) == 0) return "YES"; } return "NO";