We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.

defluckBalance(k,contests):# sort from greatest luck to least luckcontests.sort(reverse=True)luck,important=0,0forcontestincontests:ifcontest[1]==0:luck+=contest[0]elifimportant<k:luck+=contest[0]important+=1else:luck-=contest[0]returnluck

It took a lot of whiteboarding to clearly put out what I wanted. Sorted the nested list by the first value, number of points, and from there chose which points I wanted to add and which points I needed to subtract.

same idea, but your solution is much clearer and more concise

defluck_balance(k,contests):# group important and unimportant contestssorted_contests=sorted(contests,key=itemgetter(1))groups=tuple(list(g)fork,ginit.groupby(sorted_contests,key=itemgetter(1)))iflen(groups)>1:unimportant,important=groupselifgroups[0][0][1]==0:unimportant,important=groups[0],[]else:unimportant,important=[],groups[0]# calculate how many matches we need to throwthrows=len(important)-kifthrows<1:returnsum(luckforluck,_inimportant+unimportant)# start by sorting important contests to throw the smallest in terms of lucksorted_important=sorted(important)# group wins and losseslosses,wins=sorted_important[:throws],sorted_important[throws:]# do mathtotal=sum(luckforluck,_inwins+unimportant)net=total-sum(luckforluck,_inlosses)returnnet

Good clean solution, very similar to what I did, but I didn't introduce a new important variable and just directly decremented k instead and checked if k was greater than 0 instead of important < k.

## Luck Balance

You are viewing a single comment's thread. Return to all comments →

My Python3 solution:

It took a lot of whiteboarding to clearly put out what I wanted. Sorted the nested list by the first value, number of points, and from there chose which points I wanted to add and which points I needed to subtract.

same idea, but your solution is much clearer and more concise

Good clean solution, very similar to what I did, but I didn't introduce a new important variable and just directly decremented k instead and checked if k was greater than 0 instead of important < k.