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Kotlin solution without preprepared magic squares (generating all)
importjava.io.*importjava.math.*importjava.security.*importjava.text.*importjava.util.*importjava.util.concurrent.*importjava.util.function.*importjava.util.regex.*importjava.util.stream.*importkotlin.collections.*importkotlin.comparisons.*importkotlin.io.*importkotlin.jvm.*importkotlin.jvm.functions.*importkotlin.jvm.internal.*importkotlin.ranges.*importkotlin.sequences.*importkotlin.text.*/* * Complete the 'formingMagicSquare' function below. * * The function is expected to return an INTEGER. * The function accepts 2D_INTEGER_ARRAY s as parameter. */funformingMagicSquare(initial:Array<Array<Int>>):Int{varminChanges=Int.MAX_VALUEvarminSquare=arrayOf(arrayOf(0))valallMagicSquares=formingEveryPossibleMagicSquare()allMagicSquares.remove(initial)allMagicSquares.forEach{magicSquare->valchangesDone=calculateChanges(initial,magicSquare)if(changesDone<minChanges){minChanges=changesDoneminSquare=magicSquare}}returnminChanges}funformingEveryPossibleMagicSquare():MutableList<Array<Array<Int>>>{valmagicSquares:MutableList<Array<Array<Int>>>=mutableListOf()for(qin1..9){for(win1..9){if(!w.isNotEqualTo(q))continuefor(ein1..9){if(!e.isNotEqualTo(q,w))continuefor(ain1..9){if(!a.isNotEqualTo(q,w,e))continuefor(sin1..9){if(!s.isNotEqualTo(q,w,e,a))continuefor(din1..9){if(!d.isNotEqualTo(q,w,e,a,s))continuefor(zin1..9){if(!z.isNotEqualTo(q,w,e,a,s,d))continuefor(xin1..9){if(!x.isNotEqualTo(q,w,e,a,s,d,z))continuefor(cin1..9){if(!c.isNotEqualTo(q,w,e,a,s,d,z,x))continuevalrow1=arrayOf(q,w,e)valrow2=arrayOf(a,s,d)valrow3=arrayOf(z,x,c)valnewSquare=arrayOf(row1,row2,row3)if(areSumsCorrect(newSquare)){magicSquares.add(newSquare)}}}}}}}}}}returnmagicSquares}funInt.isNotEqualTo(varargother:Int)=other.none{it==this}funcalculateChanges(initial:Array<Array<Int>>,changed:Array<Array<Int>>):Int{varchanges=0for(iin0..2){for(jin0..2){valdifference=initial[i][j]-changed[i][j]changes+=Math.abs(difference)}}returnchanges}privatefunareSumsCorrect(square:Array<Array<Int>>):Boolean{valallRowSums=square.map{it.sum()}valallColumnSums=listOf(square[0][0]+square[1][0]+square[2][0],square[0][1]+square[1][1]+square[2][1],square[0][2]+square[1][2]+square[2][2])valdiagonalSums=listOf(square[0][0]+square[1][1]+square[2][2],square[0][2]+square[1][1]+square[2][0])valallSums=allRowSums+allColumnSums+diagonalSumsreturnallSums.all{it==allSums[0]}}funmain(args:Array<String>){vals=Array<Array<Int>>(3,{Array<Int>(3,{0})})for(iin0until3){s[i]=readLine()!!.trimEnd().split(" ").map{it.toInt()}.toTypedArray()}valresult=formingMagicSquare(s)println(result)}
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Forming a Magic Square
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Kotlin solution without preprepared magic squares (generating all)