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  1. Prepare
  2. Algorithms
  3. Constructive Algorithms
  4. New Year Chaos
  5. Discussions

New Year Chaos

  • lsming
     + 0 comments

    Since the question only asks the number of bribes, there's no need to really do a sorting, nor element swapping, nor "bubbling up" an element. All you need to do is to count the number of people who overtake a person.

    void calc(vector<int> q)
{
    int ans = 0;
    for (int i = q.size() - 1; i >= 0; i--) {
        if (q[i] - (i + 1) > 2) {
            cout << "Too chaotic" << endl;
            return;
        }
        for (int j = max(0, q[i] - 2); j < i; j++)
            if (q[j] > q[i]) ans++;
    }
    cout << ans << endl;
}