We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Scannerin=newScanner(System.in);inttestCases=Integer.parseInt(in.nextLine());while(testCases>0){Stringpattern=in.nextLine();//Write your codetry{Patternp=null;p=p.compile(pattern);System.out.println("Valid");}catch(PatternSyntaxExceptione){System.out.println("Invalid");}testCases--;}
Cookie support is required to access HackerRank
Seems like cookies are disabled on this browser, please enable them to open this website
Pattern Syntax Checker
You are viewing a single comment's thread. Return to all comments →
This is my solution