Re.findall() & Re.finditer()

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    import re partten = r'(?<=[bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ])([aeiouAEIOU]{2,})(?=[bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ])' m = list(map(lambda x:x.group(),re.finditer(partten,input()))) if m: for i in m: print(i) else: print(-1)