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I believe if you try with N=1000 and M=1000, you will get the run time error. Basically, 1000!*999>ulong.MAX, in other words, it should give you kind of overflow.
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Sherlock and Permutations
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I believe if you try with N=1000 and M=1000, you will get the run time error. Basically, 1000!*999>ulong.MAX, in other words, it should give you kind of overflow.