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Yes, there is two nested loops. However, because there is a fixed number of letters in the alphabet, the two nested loops runs in constant time. The actual running time of this algorithm would be 26*26*O(|s|) plus some other constants. Because we ignore constant factors, the running time is O(|s|).
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Yes, there is two nested loops. However, because there is a fixed number of letters in the alphabet, the two nested loops runs in constant time. The actual running time of this algorithm would be 26*26*O(|s|) plus some other constants. Because we ignore constant factors, the running time is O(|s|).