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Having K = 8:
- for 1728 you get following digits:
{'6', '1', '8', '7', '3', '2', '4', '5'}
- for 1729 you get: {'9', '1', '8', '7', '3', '2', '4', '5'}
While the first one is pandigital, the second one is not.
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Project Euler #38: Pandigital multiples
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Having K = 8: - for 1728 you get following digits: {'6', '1', '8', '7', '3', '2', '4', '5'} - for 1729 you get: {'9', '1', '8', '7', '3', '2', '4', '5'} While the first one is pandigital, the second one is not.