import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { static boolean isPowerOf2(long n) { return (n & (n-1)) == 0; } static boolean isPrime(long n) { long sqrt = (long) Math.sqrt(n); for (long i = 2; i <= sqrt; i++) { if (n % i == 0) { return false; } } return true; } static long longestSequence(long[] a) { long total = 0; for (int i = 0; i < a.length; i++) { total += sequenceLength(a[i]); } return total; } static long sequenceLength(long n) { if (isPowerOf2(n)) { return (n * 2) - 1; } else { long sqrt = (long) Math.sqrt(n); // try getting the largest prime divisor first for (long i = 2; i <= sqrt; i++) { if (n % i == 0) { long pair = n / i; if (isPrime(pair)) { // if divisor pair is prime, pick that return pair * sequenceLength(n / pair) + 1; // break into equal pieces } } } // if nothing for the pair, then we go down from middle for (long i = sqrt; i > 1; i--) { if (n % i == 0) { if (isPrime(i)) { // if divisor is odd, pick that return i * sequenceLength(n / i) + 1; // break into equal pieces } } } return n + 1; // reached prime number, break into sticks of length 1 and eat each one } } public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); long[] a = new long[n]; for(int a_i = 0; a_i < n; a_i++){ a[a_i] = in.nextLong(); } long result = longestSequence(a); System.out.println(result); in.close(); } }