#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i, n) for (int (i) = 0; (i) < (n); (i)++) #define FOR(i, a, b) for (int (i) = (a); (i) < (b); (i)++) #define RREP(i, a) for(int (i) = (a) - 1; (i) >= 0; (i)--) #define FORR(i, a, b) for(int (i) = (a) - 1; (i) >= (b); (i)--) #define DEBUG(C) cerr << #C << " = " << C << endl; using LL = long long; using VI = vector; using VVI = vector; using VL = vector; using VVL = vector; using VD = vector; using VVD = vector; using PII = pair; using PDD = pair; using PLL = pair; using VPII = vector; template using VT = vector; #define ALL(a) begin((a)), end((a)) #define RALL(a) rbegin((a)), rend((a)) #define SORT(a) sort(ALL((a))) #define RSORT(a) sort(RALL((a))) #define REVERSE(a) reverse(ALL((a))) #define MP make_pair #define FORE(a, b) for (auto &&a : (b)) #define FIND(s, e) ((s).find(e) != (s).end()) #define EB emplace_back template inline bool chmax(T &a, T b){if (a < b){a = b;return true;}return false;} template inline bool chmin(T &a, T b){if (a > b){a = b;return true;}return false;} const int INF = 1e9; const int MOD = INF + 7; const LL LLINF = 1e18; const int MAX = 222; const int dx[] = {0, -2, 2, -2, 2, 0}; const int dy[] = {-2, -1, -1, 1, 1, 2}; const string dWord[] = {"L", "UL", "LL", "UR", "LR", "R"}; // UL, UR, R, LR, LL, L. const int pri[] = {1, 3, 5, 4, 2, 0}; int n; int sx, sy, tx, ty; int minCost[MAX][MAX]; bool inside(int nx, int ny) { return 0 <= nx && nx < n && 0 <= ny && ny < n; } int main(void) { cin >> n; cin >> sx >> sy >> tx >> ty; if (sx == tx && sy == ty) { puts("0"); return 0; } queue> q; q.emplace(sx, sy, 0); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { minCost[i][j] = INF; } } while (!q.empty()) { int nx, ny, cost; tie(nx, ny, cost) = q.front(); q.pop(); if (!chmin(minCost[nx][ny], cost)) { continue; } for (int di = 0; di < 6; di++) { int d = pri[di]; const int nxtX = nx + dx[d]; const int nxtY = ny + dy[d]; //cerr << nxtX << " " << nxtY << " " << cost << endl; if (!inside(nxtX, nxtY)) { continue; } if (minCost[nxtX][nxtY] <= cost + 1) { continue; } q.emplace(nxtX, nxtY, cost + 1); } } if (minCost[tx][ty] == INF) { // for (int i = 0; i < n; i++) { // for (int j = 0; j < n; j++) { // cout << (minCost[i][j] == INF ? "!" : to_string(minCost[i][j])) << " "; // } // cout << endl; // } puts("Impossible"); return 0; } cout << minCost[tx][ty] << endl; VI stepWord; int nowX = tx, nowY = ty; while (nowX != sx || nowY != sy) { for (int di = 0; di < 6; di++) { int d = pri[5 - di]; int prevX = nowX - dx[d]; int prevY = nowY - dy[d]; if (!inside(prevX, prevY)) { continue; } if (minCost[prevX][prevY] + 1 == minCost[nowX][nowY]) { nowX = prevX; nowY = prevY; stepWord.emplace_back(d); break; } } } reverse(stepWord.begin(), stepWord.end()); for (int i = 0; i < stepWord.size(); i++) { printf("%s%c", dWord[stepWord[i]].c_str(), (i + 1 == stepWord.size() ? '\n' : ' ')); } }