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Apple and Orange
Apple and Orange
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C Programming Solution:
def countApplesAndOranges(s, t, a, b, apples, oranges): # Write your code here new_app_cord=[a+app for app in apples] new_orr_cord=[b+orr for orr in oranges] ca=0 co=0 for app in new_app_cord: if app>=s and app<=t: ca+=1 for orr in new_orr_cord: if orr>=s and orr<=t: co+=1 print(ca,co,sep="\n")
Java solution:
import java.io.; import java.math.; import java.security.; import java.text.; import java.util.; import java.util.concurrent.; import java.util.function.; import java.util.regex.; import java.util.stream.*; import static java.util.stream.Collectors.joining; import static java.util.stream.Collectors.toList;
class Result {
}
public class Solution { public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
}
Here is my solution in Python 3!