int main() {

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int arr[1000] = {0},n, sum = 0;
scanf("%d",&n);
for(int i = 1;i <= n;i++){
    scanf("%d",&arr[i]);
}
for(int i = 1;i <= n;i++){
    sum = sum + arr[i];
}
printf("%d",sum);
return 0;

}

For C

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int n;
    scanf("%d", &n);
    
    int *arr;
    arr = (int *) malloc(n * sizeof(int));
    for(int i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);
    }
    
    int sum = 0;
    for(int j=0; j<n; j++)
    {
        sum = sum + arr[j];
    }
    
    free(arr);
    
    printf("%d\n", sum);
    
    return 0;
}

Its simplicity and efficiency make it a foundational tool for understanding how computers work at a low level, while still being versatile enough for everything from operating systems to embedded systems. http cricbet99.club

this problems can be resolved without array #include

include

void solve(){ int n; scanf("%d",&n); int sum = 0; // int *arr = malloc((n) * sizeof(int)); for(size_t i = 0;i < n;i++){ int data; scanf("%d",&data); sum += data; } printf("%d",sum);

} int main(){ solve(); return 0; }

include

include

include

include

int main() {

/* Enter your code here. Read input from STDIN. Print output to STDOUT */  
int n;
int sum=0;
scanf("%d", &n);
int *arr = (int*)malloc(n * sizeof(int));
if (n >= 1 && n <= 1000)
{
    //phase 1: input
    for (int i = 0; i < n; i++){
    scanf("%d", &arr[i]);
    }
    // phase 2: output
    for (int i= 0; i<n; i++){
        sum += arr[i];
    }

}
  printf("%d\n", sum);
  free(arr);
return 0;

}