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  1. Prepare
  2. C
  3. Arrays and Strings
  4. 1D Arrays in C
  5. Discussions

1D Arrays in C

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  • seanmorton1985
     + 0 comments

    Working with dynamic arrays in C really highlights the importance of managing memory efficiently, much like how careful planning is crucial in plumbing marketing services to achieve consistent results.

  • magnusinst84
     + 2 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
    int n;
    scanf("%d",&n);
    
    int *arr = (int*)malloc(n * sizeof(int));
    int sum = 0;
    for (int i=0; i<n ; i++)
    {
        scanf("%d",&arr[i]);
        sum+=arr[i];
    }   
    printf("%d",sum);
    return 0;
}

  • nicolasryan9112
     + 0 comments
    int main() {
    int n;
    scanf("%d", &n);
    int array[n], sum=0;
    for(int i=0; i<n; i++) {
        scanf("%d", &array[i]);
        sum += array[i];
    }  
    printf("%d", sum);
    return 0;
}

  • vaibhavsathi4
     + 0 comments

    int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */
int arr[1000] = {0},n, sum = 0;
scanf("%d",&n);
for(int i = 1;i <= n;i++){
    scanf("%d",&arr[i]);
}
for(int i = 1;i <= n;i++){
    sum = sum + arr[i];
}
printf("%d",sum);
return 0;

    }

  • SVVBathini_w
     + 0 comments

    For C

    #include<stdio.h>
#include<stdlib.h>

int main()
{
    int n;
    scanf("%d", &n);
    
    int *arr;
    arr = (int *) malloc(n * sizeof(int));
    for(int i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);
    }
    
    int sum = 0;
    for(int j=0; j<n; j++)
    {
        sum = sum + arr[j];
    }
    
    free(arr);
    
    printf("%d\n", sum);
    
    return 0;
}