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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 29: Bitwise AND
  5. Discussions

Day 29: Bitwise AND

  • denkanono
     + 0 comments

    JavaScript Solution

    function bitwiseAnd(N, K) {
    let max = 0;
    
    for(let i = 1; i <= N; i++) {
        for(let j = N; j > i; j--) {
            let bitAndOp = i & j;
            if(bitAndOp > max && bitAndOp < K ) {
                max = bitAndOp;
            }
        }
    }
    
    return max;
}