We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 29: Bitwise AND
  5. Discussions

Day 29: Bitwise AND

  • raviiiraj
     + 0 comments

    Java

    Here is a very simple solution with the help of JAVA

    class Result {

    /*
     * Complete the 'bitwiseAnd' function below.
     *
     * The function is expected to return an INTEGER.
     * The function accepts following parameters:
     *  1. INTEGER N
     *  2. INTEGER K
     */

    public static int bitwiseAnd(int N, int K) {
        int cont=0;
        for(int i=1; i<=N; i++){            //outer loop      
							for(int j=i+1; j<=N; j++){     //inner loop
                if((i&j) < K){  //condition to check the BITAND less then the //the given number
                    if((i&j)>cont){     //to compare max and store it
                        cont = (i&j);
                    }
                }
            }
        }
        return cont;
    }

}