We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 3: Intro to Conditional Statements
  5. Discussions

Day 3: Intro to Conditional Statements

Sort by

recency

|

1804 Discussions

|

  • fransuva2020
     + 0 comments

    why my test case was faild

    function addNumbers(n) { if(n % 2 !== 0) { console.log("weird")

    } else { if (n >= 2 && n <= 5) { console.log("not weird") } else if(n >= 6 && n <= 20) { console.log("Weird") } else if(n > 20) { console.log("Not Weird") } } }

    addNumbers(3)

  • pedroaugusto466
     + 0 comments

    My solution in C#


    var isEven = N % 2 == 0;

        if (!isEven) {
        Console.WriteLine("Weird");
    }

    if (isEven && N >= 2 && N <= 5) {
        Console.WriteLine("Not Weird");
    } else if (isEven && N >= 6 && N <= 20) {
        Console.WriteLine("Weird");
    } else if (isEven && N > 20) {
        Console.WriteLine("Not Weird");
    }
}

    `

  • hassan_alhulaibi
     + 0 comments
    function main() {
    const N = parseInt(readLine().trim(), 10);
    let n = N
    
    if (n % 2 !== 0){
    console.log("Weird")
    }else if (n % 2 === 0 && n >= 2 && n <= 5) {
    console.log("Not Weird")
    }else if (n % 2 === 0 && n >= 6 && n <= 20){
    console.log("Weird")
    }else if (n > 20){
    console.log("Not Weird")
    }

    
}

  • LightningZ
     + 0 comments

    Easy solution!

  • enriquefloresdev
     + 0 comments
    N = int(input())
print("Weird" if N % 2 or 6 <= N <= 20 else "Not Weird")