We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 21: Generics
  5. Discussions

Day 21: Generics

Sort by

recency

|

353 Discussions

|

  • jagtapdhruv6
     + 0 comments

    cpp

    One should take the input in this way

    int n; cin >> n; vector intVector(n); for (int i = 0; i < n; i++) { cin >> intVector[i]; }

    int s;
cin >> s;
vector<string> strVector(s);
for (int i = 0; i < s; i++) {
    cin >> strVector[i];
}

  • gece_ramirez
     + 0 comments

    Typescript

    'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');
let inputString: string = '';
let inputLines: string[] = [];
let currentLine: number = 0;
process.stdin.on('data', function(inputStdin: string): void {
    inputString += inputStdin;
});

process.stdin.on('end', function(): void {
    inputLines = inputString.split('\n');
    inputString = '';
    main();
});

function readLine(): string {
    return inputLines[currentLine++];
}

function main() {
    // Enter your code here
    while (readLine()) {
        const previousValue = parseInt(inputLines[currentLine - 1])
        
        const arr = inputLines.slice(currentLine, currentLine + previousValue)
        
        printArray(arr)

        currentLine += previousValue
    }
}

function printArray<T>(arr: Array<T>) {
    arr.forEach(item => console.log(item))
}

  • zacharymedwinter
     + 0 comments

    public void printArray(T[] list){ for(T type: list){ System.out.println(type); }

    }

  • Ketan_Monga
     + 0 comments
    The problem is not properly explained but the Input format is like this:
3 -- count -> 1, 2, 3
1
2
3
2 -- count -> Hello, World
Hello
World

  • a_malygon
     + 0 comments

    in TS

    function printArray<T>(arr: T[]) {
    arr.forEach(i => console.log(i))
}