shailyagarwal445 output: Hello , world
public class Solution { public static void main(String[] args) {
Scanner scan = new Scanner(System.in); String s = scan.nextLine(); scan.close(); System.out.println("Hello, World. "); System.out.println( ""+s ); }}
tyagisahiba01 in the last line of your code you shoud write System.out.println(s); and also inside System.out.println("Hello World \n");
hafsasultan861 hey , its not working like this, i wrote this: Sytem.out.println("Output is " + inputString);
DC_0001 You are missing a char in 'Sytem', where it should be 'System'
change: Sytem.out.println("Output is " + inputString);
to System.out.println("Output is " + inputString);
hafsasultan861 I mistakenly wrote "sytem" here , wherease there in the problem i wrote "System" correctly. following is the exact copy pasted line: System.out.println(inputString);
hafsasultan861 Hey , it got passed, thankyou :)
Anushakolusu26 why we are getting out as welcome to 30days when we are giving system.out.println(inputstring)
kodavathkalyani1 [deleted]suryabhargwa written code is in java and it is correct
killuawpak write %n for next line because its given inn the output format
rahulpatil22206 its \n not %n
vchauhan4 it should be "System.out"
annoynomousng07 System u wrote wrong spelling
vaishali7kalkot1 same here
spsawant367 check your syntex is wrong try this one System.out.println(inputString);
AkimotoRyou well you don't need to add \n cause its already println (print in one line) so if you write code using println it'll make new line by itself
vitaliis Correct
ratunawartejas correct. +1
tenisonoseiowusu the new line charater is not necessary when using System.out.println();... it automatically add one at the end for you... use tht when writing System.out.print(); OR System.out.printf();
WaqadArshad '\n' is not needed as'println' would do the thing!
ravikantsoni_au1 System.out.println("Hello World \n");
Here, \n is not required. When we use println, then internally it will append \n to bring cursor to next line. So, if you give \n then there will be extra blank line and cusor will go to next to next line.
DC_0001 You can use also one line: System.out.println("Hello, World." + "\n" + s);
hafsasultan861 i did exactly the same, it gave me wrong answer
DC_0001 Feel free to post your output, in order to debug it :)
the correct code could be like the following:
// Create a Scanner object to read input from stdin. Scanner scan = new Scanner(System.in);
// Read a full line of input from stdin and save it to our // variable, inputString. String inputString = scan.nextLine();
// Close the scanner object, because we've finished reading // all of the input from stdin needed for this challenge. scan.close();
// Print a string literal saying "Hello, World." to stdout. // add the '\n' new line parameter then append the string // from the Scanner System.out.println("Hello, World." + "\n" + inputString);
coder_yash this is not C
velisela_tharun [deleted]
tejasridanda import java.util.Scanner; class myScanner { public static void main(String[ ] args) { Scanner sc=new Scanner(System.in); String s=in.nextLine(); sc.close(); System.out.println("Hello,World.\n"+s); } }
Sir,"I'm getting compliation successful message but testcases are failing why?"suryabhargwa Scanner scan = new Scanner(System.in);
// Read a full line of input from stdin and save it to our variable, inputString. String inputString = scan.nextLine(); // Close the scanner object, because we've finished reading // all of the input from stdin needed for this challenge. scan.close(); // Print a string literal saying "Hello, World." to stdout. System.out.println("Hello, World."); // TODO: Write a line of code here that prints the contents of inputString to stdout. System.out.println(inputString); correct with the help of this oneJadhavsonal94 sir,I'm getting compliation sucessfully message testcase 1 successfully run but 2 testcase is failing why?
mjunaidtahir same with me can u help me?
vbhadoriya3 how to write this in C??
addidagli printf("hello, world.");
aditis12399 what to do after getting first test case correct?
[deleted] Just need to printf input_string with "%s":
printf("%s", input_string);
benjohn94 How come you only need to put %s in the last line and not in the scanf line. Aren't we asking for a string there as well? Or is it because we're receiving characters of different types all in one input?
[deleted] Since your variable input_string is an array of type 'char':
char input_string[105];
In the scanf we scan each characters and store them in an array (here an array with a size of 105) of type char. So all values in the array are of type char.
A string is a chain of characters: 'a' is a char but "hello" is a string.
So if we want to output the array all at once we use a %s, if we want to output just a char we use %c.
610sonamyadav hey!!! i m stucking during input of welcome to 30 days of code! please help me to run this code...my code is not passing any test cases
[deleted] [deleted]610sonamyadav I m using C
610sonamyadav Plz help me out in this code 😞
amar22673 int main() { char string[100];int i; printf("Hello, World!\n"); scanf("%[^\n]", string);
printf("%s", string);
return 0; }
try this one.....
shwetachttrj just did this one... but it is giving 302 error.
guijun2019 good one
sharadduttasrm define a char type array with input_string as variable name. Then use gets(input_string) to get Welcome...Code!. then print hello world, then print input_string using %s. Easy.
itxwaleed int main() {
char inputstring[40]; cout<<"Hello, World.\n"; gets(inputstring); cout<<inputstring; return 0;}
jedi24garcia what language?
prakruthiks3 [deleted]vanisahasra [deleted]codelooser [deleted]
cekk2123 I totally agree with you. That's cool soundcloud to mp3
17wh1a0541 How to last line code in
viratyadav686 isn't working 😂😂
likhithasrinivas u re amezinggggggg
itxwaleed public class Solution { public static void main(String[] args) {
Scanner input =new Scanner(System.in); String s=input.nextLine(); input.close(); System.out.println("Hello, World. "); System.out.println(s);} }
vijayanagaramsi1 test case is failed after compilation is successfull what is the problem
suryabhargwa Printing hello world is already given.You need only to print given string so write only.. System.out.println(s);
24991PSIT_EN [deleted]udaysaiat13 why should we use scan.close() here in this codecould you explain
abbng12345 you conduct a little mistake at tis stage, but i appriciat your struggle and working keep working , Stop Cats from Scratching Furniture
spsawant367 which mistake i was did?
whitedk1 I don't understand the test case. My code was successful but the test case failed, what does that mean?
tarunsankhla21 ya same thing happening with me the test case 1 failling
[deleted] I think you need to unlock the other case, fix the output and submit the code. Case 0 still fails but the challange is successful.
falakjthakur83 yea, same thing here.
mrityunjayer180 please anyone help me to slove it in python,bcz whatever i try only i found error
theescapist08 It's simple, as python is .
input_string = input()
print("Hello World")
print(input_string)
balavemulakonda it is getting copiled but test cases are not satisfied..can u please help me out with this?
theescapist08 Ya sure Pls upload a screenshot and mail me at theescapist08@gmail.com Let me see what
balavemulakonda input_string. inputString = raw_input()
print 'Hello, World.'
print 'Welcome to 30 Days of Code!'
coviep The second print statement needs to print input_string. Right now you are hard-coding "Welcome to 30 Days of Code!".
The solution for Python 2 (as you are using) is as follows:
input_string = raw_input() print 'Hello, World.' print input_stringHope this helps.
balavemulakonda yup..thanku..i m done with it!!
vyshali174 yeahh!!exactly..even i m facing the same problem like her..wats the wrong?
coviep Can you show us your code?
vyshali174 inputString = raw_input()
print 'Hello, World.'
print inputString
theescapist08 it's absolutely
vyshali174 what absolutely??its not working..mail me the snippet..or explain
theescapist08 the code is absolutely correct . mail me your solution at theescapist08@gmail.com . Let me check what problem are u facing.
pdhondi93 i have tried printing the statement and the expected output and the output what i got is same but still it shows error. Here is my code
print('Hello World') print('Welcome to 30 days of coding!') print input_string
srinivasaprasath this is wrong. it is inputString = 'welcome to 30 days of coding!'; print ('hello world') print inputString but for me text case is correct but not text case 1.
coviep I just tried your code, it is working fine. What error are you getting?
balavemulakonda yea..its working !!tq
dotdeveloper999 can i submit C# code?
adrian_gugyin yes, please! O.O
mi2irfan4 yeah plz.
phillaverdiere I tried to do this one with go. I could not figure out how to use the fmt.Scan functions to read a whole line of text from stdin so I used the os pkg:
package main
import ( "fmt" "os" )
func main() {
s := make([]byte, 1200) os.Stdin.Read(s)fmt.Println("Hello World") fmt.Printf("%s\n", s)}
But the test is failing because the second line of output has a newline before the last two characters.
Are there any go experts out there that got fmt.Scan to work?
Any ideas how the second line of output got a newline inserted in it?
kapilbishnoi Even I tried using Golang but not able to process the standard input
shashanks835 Scan functions of golang only scan word till space after space it wil send to next argument So you can use something like
var s string;
var t string;
fmt.Fscanln(os.Stdin, &s, &t);
fmt.Fprintln(os.Stdout, s, " ", t);
But it can not figure out how many arguments are there So to avoid this We can use scanner for this to read a whole line with spaces
svenbs You could also just copy from stdin to sdout:
func main() { fmt.Println("Hello, World.") io.Copy(os.Stdout, os.Stdin) }
Or the mentioned solution with bufio.Scanner:
func main() { s := bufio.NewScanner(os.Stdin) fmt.Println("Hello, World.") for s.Scan() { fmt.Println(s.Text()) } }
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