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You can optimize that one step to the following... to avoid correction for doubble addition, when input number is an exact square.
public int divisorSum(int n){ int sum = 0;int i; for( i = 1; i <(int)Math.sqrt(n); i++) { if(n%i==0){ sum = sum + i + n/i; } } if(i*i == n){ sum = sum+i; } return sum; }
sum = sum+i; should be sum = sum-i;
Day 19: Interfaces
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You can optimize that one step to the following... to avoid correction for doubble addition, when input number is an exact square.
sum = sum+i; should be sum = sum-i;