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Simple one-liner:
return sum([i for i in range(1,n+1) if(n%i==0)])
or using an in-built function is_integer()
return sum([ii for ii in range(1, n+1) if (n/ii).is_integer()])
Day 19: Interfaces
You are viewing a single comment's thread. Return to all comments →
Simple one-liner:
or using an in-built function is_integer()
return sum([ii for ii in range(1, n+1) if (n/ii).is_integer()])