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it would be slightly more efficient, though, to do for(... i < sqrt ...) and if (sqrt*sqrt==n) sum += sqrt; in the end.
for(... i < sqrt ...)
if (sqrt*sqrt==n) sum += sqrt;
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Day 19: Interfaces
You are viewing a single comment's thread. Return to all comments →
it would be slightly more efficient, though, to do
for(... i < sqrt ...)andif (sqrt*sqrt==n) sum += sqrt;in the end.