Discussion on Day 6: Let's Review Challenge

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2 days ago+ 0 comments

my c++ solution, sorry if its a mess

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   

    int test_case;  // number of test cases 
    cin >> test_case;
    for(int i = 0; i < test_case; i++){ 
        string S;
        cin >> S;   // input the strings
        string even = "", odd = "";     // storage of seperation
        for (int j = 0; j < S.length(); j++){
            if (j % 2 == 0){    
                even += S[j];   // to append
            } else {
                odd += S[j];
            }
             }
            cout << even << " " << odd << endl; 
         
         }
    return 0;
}

1 week ago+ 0 comments

This solution works on PyCharm, but when I submit the code, it is rejected. Why??

def print_even_odd_characters(s):

even_characters = [] odd_characters = [] for i in range(len(s)): if i % 2 == 0: even_characters.append(s[i]) else: odd_characters.append(s[i])

print("".join(even_characters), "".join(odd_characters))

if name == "main": s = input() print_even_odd_characters(s)

2 weeks ago+ 0 comments

Simple C++ Solution :)

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

void seprateString(string S){
   
    for(int i=0;i<S.length();i++){
        if(i%2 == 0){
            cout<<S[i];
        }
    }
    cout<<" ";
    
    for(int j=0;j<S.length();j++){
        if(j%2 != 0){
            cout<<S[j];
        }
    }
    cout<<endl;
      
}


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
    int T;
    cin>>T;
    
    for(int i = 0;i<T;i++)
    {
        string S;
        cin>>S;
        seprateString(S);
    }
    
    
    
    return 0;
}

2 weeks ago+ 1 comment

n=int(input()) for i in range(n): x=input() print(f"{x[0::2]} {x[1::2]}")

Very simplest and efficient method to solve this question in Python

[deleted] 1 month ago+ 0 comments

Python 3 Solution

n = int(input())
for i in range(0, n):
    line = input()
    print(line[::2], line[1::2], sep=" ")

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