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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 6: Let's Review
  5. Discussions

Day 6: Let's Review

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recency

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3428 Discussions

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  • bahadirkocabas
     + 0 comments

    this is how I did it using string slicing and steps, n = int(input())

    for _ in range(n): s = input() print(s[::2],s[1::2])

  • hegdesantosh53
     + 0 comments

    input and output olution.cpp:8:5: error: expected unqualified-id before numeric constant int 1*0; ^ Solution.cpp:9:1: error: ‘innt’ does not name a type; did you mean ‘int’? innt sum *0 ^~~~ int Solution.cpp:13:4: error: ‘count’ does not name a type; did you mean ‘round’? count:<

  • hegdesantosh53
     + 0 comments

    input and output

  • trangiacuong216
     + 0 comments
            Scanner sc = new Scanner(System.in);
        int testCase = sc.nextInt();

            for (int i = 0; i < testCase; i++) {
                String str = sc.next();
                for (int j = 0; j < str.length(); j++) {
                        if(j % 2 ==0){
                                System.out.print(str.charAt(j));
                        }
                }
                System.out.print(' ');
                for (int k = 0; k < str.length(); k++) {
                        if(k % 2 ==1){
                                System.out.print(str.charAt(k));
                        }
                }
                System.out.println();
        }

  • hedama5845
     + 0 comments
    t = int(input())

for _ in range(t):
    S = input().strip()
    even_index = []
    odd_index = []

    for i, char in enumerate(S):
        if i % 2 == 0:
            even_index.append(char)
        else:
            odd_index.append(char)

    print("".join(even_index), "".join(odd_index))