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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 6: Let's Review
  5. Discussions

Day 6: Let's Review

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recency

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3417 Discussions

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  • paweethera
     + 0 comments
    T = int(input())  # Number of test cases

for _ in range(T):
    s = input()
    even = s[0::2]
    odd = s[1::2]
    print(even,odd,sep=" ")

  • diyadavidpnc
     + 0 comments

    Java Solution

    public class Solution {

public static void main(String[] args) {
   Scanner sc = new Scanner(System.in);
   int n = sc.nextInt();
   sc.nextLine();

   for(int i=0;i<n;i++){
    String s = sc.nextLine();
    String oddString="";
    for(int j =0 ;j<s.length();j++){
        if(j % 2 == 0)
            System.out.print(s.charAt(j));
        else
            oddString+=s.charAt(j);
    }
    System.out.println(" "+oddString);
   }
}

    }

  • oguzhn_dgd
     + 0 comments

    My js answer :

    function processData(input) {

    const lines = input.split('\n')
const t = parseInt(lines[0])


for(let i = 1; i<= t; i++){
    let even = "";
    let odd = "";

    for(let k = 0; k < lines[i].length ; k++){
        if(k % 2 === 0){
            even += lines[i][k];
        }
        if(k % 2 === 1){
            odd += lines[i][k];
        }
    }    


     console.log(even + " " + odd);
}

    }

  • f_serron
     + 0 comments

    This is my solution with Python 3

    n = int(input())
for i in range(n):    
    s = str(input())
    even_string = s[::2]
    odd_string = s[1::2]
    print(f"{even_string} {odd_string}")

    If you have any comments or improvements, please let me know!

  • vedeshalphafly
     + 0 comments

    t = int(input())

    for _ in range(t): s = input() even_chars = s[::2]
    odd_chars = s[1::2]
    print(even_chars, odd_chars)