Objective
Today, we're discussing a simple sorting algorithm called Bubble Sort. Check out the Tutorial tab for learning materials and an instructional video!

Consider the following version of Bubble Sort:

for (int i = 0; i < n; i++) {
    // Track number of elements swapped during a single array traversal
    int numberOfSwaps = 0;
    
    for (int j = 0; j < n - 1; j++) {
        // Swap adjacent elements if they are in decreasing order
        if (a[j] > a[j + 1]) {
            swap(a[j], a[j + 1]);
            numberOfSwaps++;
        }
    }
    
    // If no elements were swapped during a traversal, array is sorted
    if (numberOfSwaps == 0) {
        break;
    }
}

Task
Given an array, , of size distinct elements, sort the array in ascending order using the Bubble Sort algorithm above. Once sorted, print the following lines:

1. Array is sorted in numSwaps swaps.
   where is the number of swaps that took place.
2. First Element: firstElement
   where is the first element in the sorted array.
3. Last Element: lastElement
   where is the last element in the sorted array.

Hint: To complete this challenge, you will need to add a variable that keeps a running tally of all swaps that occur during execution.

Example

original a: 4 3 1 2
round 1  a: 3 1 2 4 swaps this round: 3
round 2  a: 1 2 3 4 swaps this round: 2
round 3  a: 1 2 3 4 swaps this round: 0

In the first round, the is swapped at each of the comparisons, ending in the last position. In the second round, the is swapped at of the comparisons. Finally, in the third round, no swaps are made so the iterations stop. The output is the following:

Array is sorted in 5 swaps.
First Element: 1
Last Element: 4