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  1. Prepare
  2. Python
  3. Strings
  4. Alphabet Rangoli
  5. Discussions

Alphabet Rangoli

  • namita_nair0201
     + 1 comment

    I made a very slight variation in the above code, and somehow i get an error in test case 3 for the input: 15. Although, as far as i can tell, my o/p is the same as the expected o/p. I'm at a complete loss. Here is my code:

    def print_rangoli(n):
    import string
    alpha = string.ascii_lowercase
    l=[]
    for i in range(n):
        s = '-'.join(alpha[i:n])
        l.append((s[::-1]+s[1:]).center(4*n-3,'-'))
    b=reversed(l[1:])
    print("\n".join(b), "\n".join(l), sep = "\n")

    my o/p:

    image expected o/p:

    image