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  1. Prepare
  2. Algorithms
  3. Strings
  4. Alternating Characters
  5. Discussions

Alternating Characters

  • pradeep_tarakar
     + 0 comments

    Simple loop based C++ Solution: 

    int alternatingCharacters(string s) {
    if(s.size() == 1)return 0;
    int deletions = 0;
    for(int i=1; i<s.size(); i++){
        if(s[i-1] == s[i])deletions++;
    }
    return deletions;
}