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  1. Prepare
  2. Algorithms
  3. Strings
  4. Alternating Characters
  5. Discussions

Alternating Characters

  • tomisin
     + 1 comment

    O(N) Javascript solution:

    function alternatingCharacters(s) {
  let deletions = 0;

  for (let i = 0; i < s.length; i++) {
    if (s[i] === s[i + 1]) deletions++;
  }

  return deletions;
}