def angryProfessor(k, a): count = 0 for i in a: if i <= 0: count += 1 if count >= k: return "NO" else: return "YES"

Here is my Python one-liner

def angryProfessor(k, a):
    return 'YES' if len([i for i in a if i <= 0]) < k else 'NO'

This question is poorly written. HackerRank Authors need to improve the question's quality. Keep the questions straight forward, to understand.

Here is my solution in JavaScript

let onTime = 0;
for(let i = 0; i < a.length; i++){
	if(a[i] <= 0){
		onTime++
	}
}
return onTime < k ? "YES" : "NO"

Here is problem solution in pYthon, Java, C++, C and Javascript - https://programmingoneonone.com/hackerrank-angry-professor-problem-solution.html