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  2. Python
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Any or All

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765 Discussions

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  • dheenupriya2001
     + 0 comments
    n = int(input())
lst = list(map(int, input().split()))
res = False
count = 0
for i in range(len(lst)):
    if lst[i] > 0:
        count+=1
        if str(lst[i]) == str(lst[i])[::-1]:
            res = True
            
if count== len(lst) and res:
    print("True")
else:
    print("False")

  • hzerryn
     + 0 comments
    n = int(input())
nums = list(map(int, input().split(' ')))
print((all(x > 0 for x in nums) and (any(str(x) == str(x)[::-1] for x in nums))))

  • SVVBathini_w
     + 0 comments

    For Python3 Platform

    Completed in 3 lines ignoring the space between inputs and print statement. It also can be done in two lines writing all the inputs in a single line

    N = int(input())
nums = input().split()

print(all(int(i)>0 for i in nums) and any(c==c[::-1] for c in nums))

  • yugandher_jagad1
     + 0 comments

    l=[5] m=[12,9,61,5,14] print(any([l,m]))

  • 23x01a1240
     + 0 comments

    two lines:

    inp,li = int(input()), input().split()
print(all(int(i) >0 for i in li)and any(j == j[::-1] for j in li))