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Any or All

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761 Discussions

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  • 23x01a1240
     + 0 comments

    two lines:

    inp,li = int(input()), input().split()
print(all(int(i) >0 for i in li)and any(j == j[::-1] for j in li))

  • gavinyclee
     + 0 comments
    _ ,num_list = input(),input().split()
print(all([all([int(i) > 0 for i in num_list]),any([i == i[::-1] for i in num_list])]))

  • JanekPython09
     + 0 comments

    One line solution

    print((n := int(input())) and (lista := list(map(int, input().split()))) and all([all(val > 0 for val in lista), any(str(val) == str(val)[::-1] for val in lista)]))

  • nandakumars825
     + 0 comments
    N = int(input())
integers = list(map(int,input().split()))

def is_palindromic(integer):
    string = str(integer)
    reverse_string = string[-1::-1]
    if string == reverse_string :
        return True
        
print((all(map(lambda x: x>0, integers))) and (any(map(lambda x: is_palindromic(x), integers))))

  • bandeira85
     + 0 comments

    N = int(input())

    int_list = list(map(int, input().split()))

    print(all([i>0 for i in int_list]+[any([i==i[::-1] for i in map(str, int_list)])]))