Discussion on Left Rotation Challenge

ShkKiit 3 years ago+ 12 comments

Neatest code to get this done!!!

int n,d;
    cin>>n;
    int a[n];
    cin>>d;
    for(int i=0;i<n;cin>>a[i],i++);
    d=d%n;
    for(int i=d;i<n;i++)
        cout<<a[i]<<" ";
    
    for(int i=0;i<d;i++)
         cout<<a[i]<<" ";
    return 0;

rajatbarman 2 years ago+ 1 comment

awesome :)

ShkKiit 2 years ago+ 1 comment

Thanks :)

sainimohit23 2 years ago+ 0 comments

you deserve my respect sir........ AWESOME

thahimumhassanm1 2 years ago+ 0 comments

MASHA ALLAH...good logic...simple nd awesome...thanx,4 sharing this..

krsoni 2 years ago+ 2 comments

You didn't actually rotated the array, printing the required answer is not the solution. The rotated array might be of some use later in the actual program and the problem is designed to practice the array rotation. Hope you try to understand.

ShkKiit 2 years ago+ 1 comment

I understand that. But in this question i was required just to print the rotated form so i did the same. If i was to use the array later on, it wouldn't have been tough to declare a new array and start storing in it using a counter variable. So i kept it simple here just to pass all the test cases :)

vamphonephong 2 years ago+ 0 comments

"A left rotation operation on an array of size n shifts each of the array's elements d unit to the left."

That opening problem statement alone means that you need to shift an existing array; not just print the array in the shifted order.

grublob 2 years ago+ 0 comments

Right

SuperGogeta 2 years ago+ 1 comment

I do understand d=d%n but in this instance it isn't necessary, question's constraints says 1<d<n

ShkKiit 2 years ago+ 0 comments

Sometimes coders are extra-careful i guess !

TimSylvester 2 years ago+ 0 comments

You're over-complicating things with two loops and C arrays in C++.

int n, d;
cin >> n >> d;
vector<int> v((istream_iterator<int>(cin)), istream_iterator<int>());
for (int i = 0; i < n; ++i) cout << v[(i + d) % n] << " ";