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I thought my solution is neat. but here are more neat solutions!
n, d = map(int, input().strip().split()) arr = [int(arr_t) for arr_t in input().strip().split()] for _ in range(d): arr.append(arr.pop(0)) print (*arr)
Great solution!
Hey, I like your solution. A recommendation for the future is if you want to pop the first element, you should use a deque. https://docs.python.org/3/library/collections.html#collections.deque
arr.pop(0) is O(N) while the deque version arr.popleft() is O(1)
Hey! Can you tell me how does *arr work?
https://pythontips.com/2013/08/04/args-and-kwargs-in-python-explained/
good one!
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You are viewing a single comment's thread. Return to all comments →
I thought my solution is neat. but here are more neat solutions!
Great solution!
Hey, I like your solution. A recommendation for the future is if you want to pop the first element, you should use a deque. https://docs.python.org/3/library/collections.html#collections.deque
arr.pop(0) is O(N) while the deque version arr.popleft() is O(1)
Hey! Can you tell me how does *arr work?
https://pythontips.com/2013/08/04/args-and-kwargs-in-python-explained/
good one!