DevFactorYT Hello Fellow HackerRanker's,
I created a video-tutorial walking through this problem and intend to walk through the rest of the problems (I am finished with most of DS on my main account).
Check out the walkthrough here: https://www.youtube.com/watch?v=hKQphShaM6g
Best Regards,
DevFactor
pablocrp_crm thx so much. i want to improve my programming skills
lochek_alon It seems like this solution is no longer working because the current program's structure seems more complex now than the one on your video. But anyway, thanks for the explanation and for the work you do.
satishbabuoffice Single line code in JavaScript
console.log(arr.reverse().join(' '));
pminkov Nice!
alxcherepanov Nice, it seems, you forgot another 28 lines of parsing.
That's what I call one line:
#!/usr/bin/env ruby gets && (puts gets.split.reverse.join(' '))
nyos22 2 lines in python, just because of n...
input() print(" ".join(str(x) for x in reversed(list(map(int, input().strip().split())))))
csixteen You can simplify your Python code:
input() print(" ".join(input().split(" ")[::-1]))
artgromov i think you forgot about number of digits to print (N)
csixteen Not necessary. I just take whatever comes as the second input, create a list from it, reverse it and print the elements glued with a space.
KeyurPotdar You can do it in a single line:
print(input()==0 or " ".join(input().split()[::-1]))
msmsinghchauhan Your code didn't work.
>> print(input()==0 or " ".join(input().split()[::-1])) 10 20 30 40 50 50
a_kamal_89 I guess that you forgot to press Enter after the first integer input.
aliciali This works too.
n = int(input()) print(*list(input().split())[::-1])
shaurya2us What language is this? (Python or C++)
KeyurPotdar Python 3
duy_tha304 Hello I'm new to python so could you please explain the * and [::-1] in the second line,please?
msmsinghchauhan - will unpack a list.
eg:
A=[1,2,3] print(*A) 1 2 3
we use [::] to slice. refer http://pythoncentral.io/how-to-slice-listsarrays-and-tuples-in-python/
eg: If we want to get a sliced list in reverse order.
print(A[::-1]) [3, 2, 1]
duy_tha304 Okay,got it.Thank you so much
- will unpack a list.
eg:
armyindiabts can u explain why u put * beforew list?
lorentz_dll [deleted]
KeyurPotdar [deleted]an0o0nym one-liner
print(*[input().split() for _ in range(2)][1][::-1])
shaurya2us What language is this?
anirudhsingla8 python
vasanthmsvs can u xplain this plz..
jacky_xue_ds It doesn't work. No reponse output
jhrozo ## yet simplier, python has it all !! print(*arr[::-1])
rojastorrado The idea is make and understand what's happening behind scenes.. Make the algorithm.
jhrozo Ok, here is the explanation. The simple print(*arr[::-1]) is equivalent to:
output_str = "" inverse_array = arr[::-1] for element in inverse_array: output_str = output_str + " " + str(element) print(output_str)
This is why Python has it all.
dgaban lol. the challenge is to make the reverse algorithm yourself. you're still relying on just using arr[::-1] instead of actually writing that algorithm yourself.
gurneeshchahal09 return a[::-1]
yuki_ Not as simple as yours, but how about this?
console.log(require('fs').readFileSync('/dev/stdin', 'utf8').split('\n')[1].split(' ').reverse().join(' '));
ltrico59 [deleted]
CSharpDev One-liner in C# too:
Console.WriteLine(string.Join(" ", arr.Reverse()));
aakashjaker1999 [deleted]
dizmartin_gonza1 My c++ solution:
vector<int> reverseArray(vector<int> a) { int aux = 0; int n = a.size(); for (int i = 0; i < n/2; ++i) { aux = a[n-i-1]; a[n-i-1] = a[i]; a[i] = aux; } return a; }varunsh9 why this much over programming required?
buzcuberk I'd say a much bettery solution (for c++14) is:
vector<int> reverseArray(vector<int> a) { vector<int> y; for(auto x = a.end()-1; x >= a.begin(); x--) y.push_back(*x); return y; }
sathvikrijo why u typing this much.... i finished the code within a couple of lines in the function;
- reverse(a.begin(),a.en());
- return a;
that's all the finished...
buzcuberk the attempt was to show traversing backwards simply reverts it when you push back
sathvikrijo i cant understand you bro.
rajarshi356 Its very easy passed all the test cases
import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ int n,i,b,j; Scanner sc=new Scanner(System.in); n=sc.nextInt(); int[] a=new int[n]; for(i=0;i<n;i++){ a[i]=sc.nextInt(); } for(j=a.length-1;j>=0;j--){ System.out.print(a[j]+" "); } } }
jasonganub Looks good! To make this even faster, you should loop through n/2 items and swap a[i] with a[n-1-i].
_hemant can you show this using codes?
jasonganub I have my code submitted above in the discussion area.
My way permanently makes it reverse. If the interviewer asked to reverse the array, then this solution would not work since it does not reverse it, but it prints it in reverse. If they just want it to print in reverse, then rajarshi356's works fine.
jasonganub for i in range(0, n//2): temp = arr[i] arr[i] = arr[-1-i] arr[-1-i] = temp result = "" for i in arr: result = result + str(i) + " " print(result)
thulasiram_vall1 Don't this add more operations to the logic.
dtyagi1 n = int(raw_input().strip())
arr = map(int,raw_input().strip().split(' '))
result=""
for i in range(n):
result=result+str(arr[n-1-i])+" "print result
mohamedyousfi74 the using code donètwork it only show the secret page help plz
ashi_rais problem says to read array element from Line- 4 (size) 1 2 3 4 ( array elements are all in one line)
but in your code you are reading it like
4 (size) 1 2 3 4
need to use scanner.nextLine()
h2084772909 first intput and last output,your code is easy to understand and most userful.
ashish_pathania1 why am i using a.length-1 and not a.length
rajarshi356 Since array start from 0 index so we are using the same
dziadevich for(;n>0;) System.out.print(arr[--n] + " ");
jeya28798 is any inbuild functions available for reverse a string in java
mayank113463 no! you have to convert string into stringbuilder or stringbuffer
dedeco The Zen of Python:
for x in reversed(arr): print x,
asoback I did something similar, every time I tried to print x in the for loop I was getting a vertical output, so I made it a string.
*Edit: I copy and pasted your code, and didn't pass due to having the vertical output. Did it work for you?
This passed for me.
import sys n = int(input().strip()) arr = [int(arr_temp) for arr_temp in input().strip().split(' ')] c = "" for x in arr[::-1]: c += str(x) + " " print(c)
dedeco Yes man, worked! Please try again and let me know. Did you try here? or in your terminal?
See:
krutika_shah I do the same code but compiler shows me wrong answer... in python 2.. I think it isnt working in Python 2
ccscoder Another way using Javascript :)
console.log(arr.reduce(function(a,b) { return b+' '+a+' '; }));
rubensol686 Hey Greetings! I'm new on this platform, 1 question do we HAVE to use console.log ?? I'm a bit puzzled...
lwauke I thought that a.short(() => 1) would work in Javascript, but it doesn't pass in some tests, I don't know why...
macdhollister I'm getting a bug when trying to solve this with JavaScript. I didn't change any of the main method code, so everything from the error is pre-written.
solution.js:41 ws.write(res.join(' ') + '\n'); ^ TypeError: Cannot read property 'join' of undefined at main (solution.js:41:18) at ReadStream.<anonymous> (solution.js:20:5) at emitNone (events.js:111:20) at ReadStream.emit (events.js:208:7) at endReadableNT (_stream_readable.js:1064:12) at _combinedTickCallback (internal/process/next_tick.js:138:11) at process._tickCallback (internal/process/next_tick.js:180:9)
jonhope3 A little more thought required, but an interesting solution:
static int[] reverseArray(int[] a) { int[] solution = new int[a.length]; for(int i=a.length-1, j=0; i>-1; i--, j++) { solution[j] = a[i]; } return solution; }
tanujkaruturi import java.io.; import java.util.;
public class Solution {
public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ int n,i,b,j; Scanner sc=new Scanner(System.in); n=sc.nextInt(); int[] a=new int[n]; for(i=0;i<n;i++){ a[i]=sc.nextInt(); } for(j=a.length-1;j>=0;j--){ System.out.print(a[j]+" "); } }} this is the complete prg ****
phani__kumar fassak
karangale Simple Python Solution
def reverseArray(a): temp = [] size = len(a) for i in range(size-1, -1, -1): temp.append(a[i]) return temp
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