The “C++ Introduction: Arrays” section on HackerRank is a great starting point for beginners learning how arrays work in C++. Radhe Exch Login xyz

Arrays allow you to store multiple values of the same type in a single variable, making it easier to manage collections of data! Funinmatch360 com mobile

Easy solution

int main() {
    int n;
    cin >>n ;
    int arr[n];
    for (int i=0;i<=n-1; i++) {
        cin>>arr[i];
    }
    
    for (int i=n-1; i>=0; i--) {
        cout<<arr[i]<<" ";
     }
    return 0;
}

Reading input and writing output can honestly be done either with cin / cout or scanf / printf. Coming from a MATLAB / Python / C background, I personally prefer using printf than cout. Regardless, this two-pass solution is relatively easy

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
     
    int n ;
    scanf("%d", &n);
    int arr[n];
    
    for (int i=0; i <=n ; i++) {
        scanf("%d", &arr[i]);  
    }
    
    for (int i = n-1; i >=0 ; i--) {
        printf("%d ", arr[i] );    
    }
    
    return 0;
	}

Although it really bothers me that it throws this warning :

Variable length arrays in C++ are a Clang extensionclang(-Wvla-cxx-extension) Solution.cpp(14, 13): Read of non-const variable 'n' is not allowed in a constant expression.

It still compiles and works, but I think that exercises shouldn't throw warnings when a correct solution is written....

}

The code asks for an array, but you can't initialise and array with a non-const integer. The exercise should either explicitly state you can use a vector object (as you would), or if an array is required that it should be created on the heap so it's possible.