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  1. Practice
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  3. Bash
  4. A Personalized Echo
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A Personalized Echo

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  • Netherheld + 5 comments

    Why is the read syntax the only correct answer to this question? Why not the $1 alternative?

    • mbrito + 0 comments

      agree

    • cli__ + 0 comments

      The input comes from stdin, not comand line arguments

    • panchito + 0 comments

      Humm, thanks, didn't know this only correct answere i did also it with $1 with no success .. theses tests are limited

    • dukemaneesh + 0 comments

      read name echo "Welcome Dan"

    • dave00ster + 0 comments

      Agreed. I don't understand why they had to write "script which accepts" instead of "script which reads.

  • michi7x7 + 0 comments

    hehe :)

    printf "Welcome "
cat

  • x0r19x91 + 2 comments
    sed -r 's/(.*)/Welcome \1/g'
    • Cristiana + 2 comments

      Hi! I'm new to this. Can you please explain a bit this command?

      • x0r19x91 + 1 comment

        I'm capturing the contents of stdin using (.*) regexp which can be referenced using \1 where \1 refers to 1st captured group and then prepending the text with "Welcome".
        The syntax is s/[text]/[replacement]/

        • Cristiana + 0 comments

          Got it. Thanks!

      • brevnovak + 1 comment

        and what's that '/g' for? thanks :)

        • x0r19x91 + 0 comments

          Global Replacement. That's not needed here though

    • zzmmss + 0 comments

      new to shell, very incredible

  • sakthipitchaiah + 3 comments

    here is the answer:

    read name
echo "Welcome $name"
    • dread1 + 0 comments
      [deleted]
    • dread1 + 1 comment
      echo "Welcome $(</dev/stdin)"

      will also work

      • mmshaban + 1 comment

        Can you explain this a bit, please?

        • SomuSysAdmin + 1 comment

          Whenever you use something like `$(command) in bash, you're creating a new sub-shell for that command. The input is obtained in that subshell, and the output replaces the entire $(command)` section in the original shell. Essentially think of it like executing a command first and then putting the ouput in place of the bracketed section.

          Now, </dev/stdin is just redirecting the input from the subshell. So, whatever is entered in the subshell (sample inputs from the test-cases) gets sent (and replaces) $(</dev/stdin).

          • mmshaban + 0 comments

            Nice.. Thanks..

    • kiyana_ahmadi + 0 comments

      I wrote exactly the same thing but it keeps saying it's wrong !!

  • cloaked1 + 0 comments
    xargs -I ^ echo "Welcome" ^

  • aadi2203 + 3 comments

    I have a tick in every test case but when retunr back to the bash tutorials page it doesnt show thus question as fully solved?

    • vivmbbsHackerRank Admin + 1 comment

      checking this; it's a bug on our end. will fix

      • apachebeard + 0 comments

        bug still not fixed

    • dheerajHackerRank Admin + 1 comment

      Hi @aadi2203,

      can you please check now? It will be fixed.

      • varunchopra + 0 comments

        3 years and it still hasn't been fixed.

    • brahanmadhav + 0 comments

      same here :(

  • ajitchaurasia53 + 0 comments

    read a echo "Welcome $a"

  • tpgreene + 0 comments
    #!/usr/bin/env bash

read name
echo "Welcome $name"

  • rmeagher + 0 comments

    Who would put an input via stdin with a script? That challenge is very flawed. $1 would be most acceptable as an input to the script and not stdin.

  • Sposibo + 0 comments
    echo -n Welcome 
read name
echo " $name"
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