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hint: use bc -l. Use 'scale' or an equivalent for appropriate decimal places! As you can see, many have got this challenge right. 17.92857 rounds off to 17.949 when corrected to 3 decimal places.
you are missing a " ; " after read X ... also, bc truncates in a strange way and the challenge author, in spite of writing (now) "...rounded up ...", expects a value rounded in another strange way. (Seems there are solutions using printf, but for doing it within bc only I had to use "... if ( x < 0 ) { x = x - 0.0004999;} else { x = x + 0.0004999; } ..." which looks highly nonstandard to me. (For normal mathematicians, round(x) := floor(x+0.5), so round(1.5) = 2 and round(-1.5) = -1. This is not the convention used here...)
Arithmetic Operations
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Here's the result from a calculator: 5+50*3/20 + (19*2)/7 = 17.92857142857143
and yet you're expecting the solution to be: 17.929 ....
The solution is literally 1 line and I cannot see why you're expecting 17.929 instead of 17.928
hint: use bc -l. Use 'scale' or an equivalent for appropriate decimal places! As you can see, many have got this challenge right. 17.92857 rounds off to 17.949 when corrected to 3 decimal places.
I have used bc -l along with scale , still it rounds off it to 17.92857
Use a bc scale that's higher than printf's. e.g. Use scale=4 together with printf "%.3f". Only then you'll get hackerrank's expected result.
Please take a look at my submission:
read X echo "scale = 3; $X" | bc -l
this is not passing the first test for that specific error. All other tests are passing fine.
you are missing a " ; " after read X ... also,
bctruncates in a strange way and the challenge author, in spite of writing (now) "...rounded up ...", expects a value rounded in another strange way. (Seems there are solutions using printf, but for doing it within bc only I had to use "... if ( x < 0 ) { x = x - 0.0004999;} else { x = x + 0.0004999; } ..." which looks highly nonstandard to me. (For normal mathematicians, round(x) := floor(x+0.5), so round(1.5) = 2 and round(-1.5) = -1. This is not the convention used here...)it's a one line answer - can't really give a bigger hint without revealing the answer altogether :)
Instead of saying "display the output correct to 3 decimal places" you should say "display the output rounded to 3 decimal places".
'Correct' just means that users should give you what you want, and you never say that you want it rounded and not truncated.
I had the same problem and I used printf approach, which should not be what is expected...
printf "%.3f" $(echo "scope=3;5+50*3/20 + (19*2)/7"|bc -l)
No, leafmoon - people have got it correct. Or, message me the code you submitted and I'll try to see what the issue is.
using
scalewon't round the number. You could just try it yourself.