enilaydagdemir Here is my solution!
read firstNumber read secondNumber if (($firstNumber > $secondNumber)); then echo X is greater than Y; elif (($firstNumber < $secondNumber)); then echo X is less than Y; else echo X is equal to Y; fi
catpin Pretty much snap!
#!/bin/bash read X read Y if (( $X > $Y )); then printf "X is greater than Y" elif (( $X == $Y )); then printf "X is equal to Y" else printf "X is less than Y" fi
dnovosard #!/bin/bash read X read Y if(($X > $Y)); then echo X is greater than Y; fi if(($X == $Y)); then echo X is equal to Y; fi if(($X < $Y)); then echo X is less than Y; fi
x0r19x91 Without conditionals
#!/bin/bash read x read y result=( `printf "%s\n" "$x"{\>,\==,\<}"($y)" | bc` ) offset=$(( ${result[1]} + 2*${result[2]} )) answers=( "X is greater than Y" "X is equal to Y" "X is less than Y" ) echo ${answers[$offset]}
maniibi looks beautiful.. please explain
x0r19x91 In line 3, I'm storing the results of X>Y, X==Y, X<Y in $result as an array. If the result is (1, 0, 0) -> print 'X > Y' (0, 1, 0) -> print 'X == Y' (0, 0, 1) -> print 'X < Y' Let's define a function that maps the tuple into an integer offset f(1, 0, 0) = 0 // "X > Y" i.e. ${answers[0]} f(0, 1, 0) = 1 // "X == Y" i.e. ${answers[1]} f(0, 0, 1) = 2 // "X < Y" i.e. ${answers[2]} So we can see that f(x, y, z) = x*0 + y*1 + z*2 = y+2z
maniibi line third is bit confusing.. explain how it works. fourth line is fine. You are calculating offset using the values at diff index. last line,is it kind of string array?? with size 3.
x0r19x91 Brace expansion is resolved first by bash. since x,y can be negative, I put y in parentheses so as to distinguish the - sign and the comparison operator. the brace expansion produces X>Y, X==Y, X<Y. You need to escape the operators. printf with "%s\n" returns the above strings separated by newline. These strings are passed to bc which evaluates and returns the comparison results. The outer parentheses converts the results returned by bc into an array.
maniibi tell.. where did you learn all this from and the strategy also.
domingos_paraiso Just for fun
#!/bin/bash declare -i X; declare -i Y; read X; read Y; echo "X is $( ([ $X -gt $Y ] && echo greater than) || ([ $X -lt $Y ] && echo less than) || ([ $X -eq $Y ] && echo equal to) ) Y"
mvbelgaonkar Nicely put.
rajujnvgupta hey ! it's great
seolocals Edit: I solved it already. This is the answer.
read -p number X read -p number Y if ((X > Y)); then echo "X is greater than Y" elif ((X < Y)) then echo "X is less than Y" else echo "X is equal to Y" fi
danielgcwik thanks that worked
mmshaban How come you didn't need the "$" infront of the X and the Y in "if ((X > Y))" ?
a2435 According to multiple manuals I can use input in a way like:
#!/bin/bash read X Y;
However my script doesn't pass all test scenarios. And everything is ok when I change it just to:
#!/bin/bash read X; read Y;
Now all test cases passed successfully. Took half an hour to figure it out here :)
x0r19x91 #!/bin/bash export IFS=$' ' read X Y
kanonwalasonai #!bin/bash read x1 read y1 read x2 read y2 read x3 read y3 if [ "$x1" -lt "$y1" ] then echo X is less than Y fi if [ "$x1" -gt "$y1" ] then echo X is greater than Y fi if [ "$x1" -eq "$y1" ] then echo X is equal to Y fi
mirkancal read X read Y if [ $X -gt $Y ] then echo "X is greater than Y" elif [ $X -lt $Y ] then echo "X is less than Y" else echo "X is equal to Y" fi
abhishtagatya #!/bin/bash op=0 while [ $op -lt 1 ] do read x read y if [[ $x -lt $y ]]; then printf "X is less than Y\n" elif [[ $x -gt $y ]]; then printf "X is greater than Y\n" else printf "X is equal to Y\n" fi ((op++)) done
Here's my solution... I dont get why [$op -lt 1]... Eventhough its suppose to loop 3 times, but this works, why?
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