Compute the Average

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    sum=0 read N

    for (( i=1; i<=N; i++)) do read x ((sum += x)) done avg=sum / avg"

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    *#!/bin/bash read Number for((i=1;i<=((x)) done printf "%.3f" sum/$Number" | bc -l) *

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    here is my code , my code fails in hidden test case no 2 , can anyone help me , i need my code to as input++ simultaneoulsy count++ , i can't figure it out can anyone help me read n
    sum=0 count=0

    while [ n ] do read num sum=((count + 1)) done avg=sum / avg

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    read num
    sum = 0
    for((i=1;i<=$num;i++))
    do
      read x
      sum=$(($sum + $x))
    done
    printf "%.3f" $(echo "$sum/$num" | bc -l)
    
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    read n sum=0 for ((i=1;i<=n;i++)) do read temp sum=sum/$n" |bc -l