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- Bash
- Compute the Average
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Compute the Average
Compute the Average
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*#!/bin/bash read Number for((i=1;i<=((x)) done printf "%.3f" sum/$Number" | bc -l) *
here is my code , my code fails in hidden test case no 2 , can anyone help me , i need my code to as input++ simultaneoulsy count++ , i can't figure it out can anyone help me read n
sum=0 count=0
while [ n ] do read num sum=((count + 1)) done avg=sum / avg
read n sum=0 for ((i=1;i<=n;i++)) do read temp sum=sum/$n" |bc -l
!/bin/bash
read n sum=0
for (( i=0; i
Calculate and print average rounded to 3 decimal places
avg=sum / avg"