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1) i = $((i+2)) will give an error because of extra space around "=".
It can be corrected to : i=$((i+2))
2) The above mentioned line i=$((i+2)) is actually unnecessary because the updated value of i is never used, and overwritten by for in next iteration. Hence, this line can be completely removed.
3) Use for i in {1..100..2} instead of for i in {1..100} to get increment of 2.
Looping and Skipping
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whats wrong??
Three things :
1)
i = $((i+2))will give an error because of extra space around "=". It can be corrected to :i=$((i+2))2) The above mentioned line
i=$((i+2))is actually unnecessary because the updated value of i is never used, and overwritten by for in next iteration. Hence, this line can be completely removed.3) Use
for i in {1..100..2}instead offor i in {1..100}to get increment of 2.what if i want to increment inside the loop?
Then you can use
while [ $i -le 100 ], also make sure to initializei=1in this case.You can also use C like construct :
for (( i=1; i<=100; i+=2 )), but then again, this won't allow you to increment inside loop.for i in {1..99}; do echo $i; done
it doesn't work? do you know Bash? Don't do theses exercices for suckers !
you should add that echo statment after i = $((i+2))
No, that won't work! As mentioned in my previous comment, value of i will be over-written by for loop in the next iteration.
Doing this will print all numbers from 3 to 102 instead. Try it yourself.