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  1. Prepare
  2. Linux Shell
  3. Bash
  4. Looping and Skipping
  5. Discussions

Looping and Skipping

  • MasterFoo
     + 0 comments

    Three solutions; the last one is the " real" solution since it is checking for odd numbers according to the problem instructions.

    # Solution (1)
#for n in {1..99..2} # start at 1, count up to 99 by incrementing by 2
#do
#    echo $n
#done
#    
# Solution (2)      # same here
#for (( n = 1; n <= 99; n += 2 ))
#do
#    echo $n
#done
#
# Solution (3)      # by checking for odd numbers
for n in {1..99}
do
    if (( $n%2 != 0 ))
    then
        echo $n
    fi
done