My Solution

#!/bin/bash
read X
read Y
printf "%s\n" $X{+,-,*,/}"($Y)" | bc

This worked fine

read x
read y

echo $((x + y))
echo $((x - y))
echo $((x * y))
echo $((x / y))

The test cases conflict with the requirements. Test #4 & #5 expect things to work with x,y being greater than 100 or less than -100 which goes against what the rules state. So in the end my validation to fit the rules broke my submissions.

The word 'difference' is confusing. It mostly suggests a mod of both values.

what did I miss? when I run I get the correct output. But "wrong answer" to solve the problem?

x=5 y=2 num1="x+((y))" num3="x*((y))" echo "num2" echo "num4"

Was it becasue I didn't lead with #!/bin/bash...?

I thought so

signs=(+-*/)
for ((i=0;i<4;i++));do echo $((5"${signs:$i:1}"2)); done
7
3
10
2

Four hours or so and i've got this.

#!/bin/bash
read x
read y

if [ "$x" -ge "-100" ] && [ "$y" -ge "-100" ] && [ "$x" -le "100" ] && [ "$y" -le "100" ] && [ "$y" -ne "0" ]; then
	echo "$x + $y" | bc
	echo "$x - $y" | bc
	echo "$x * $y" | bc
	echo "$x / $y" | bc
else
	echo "ERROR"

fi

works like a charm. probably messy. i'm extremely new to bash-scripts.

read x
read y
echo -e "$((x+y))\n$((x-y))\n$((x*y))\n$((x/y))"

This worked for me!

read x read y if [ x -le 100 ] then if [ y -le 100 ] then echo expry echo expry echo expry echo expry else echo "error:value of y out of range" fi else echo "error: value of x out of range" fi