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  1. Prepare
  2. Linux Shell
  3. Arrays in Bash
  4. Filter an Array with Patterns
  5. Discussions

Filter an Array with Patterns

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149 Discussions

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  • chetanpangam1991
     + 0 comments
    while read input
do
    my_arr=("${my_arr[@]}" $input)
done

pattern=(${my_arr[@]/*[aA]*/})
echo "${pattern[@]}"

  • wkdansqls
     + 0 comments

    using shell parameter expansion,

    mapfile countries
echo ${countries##*[Aa]*}

    ${parameter##pattern} deletes longest matching pattern.

    If you need further information, here is bash reference manual. https://www.gnu.org/software/bash/manual/bash.html#Shell-Parameter-Expansion

  • guest122ev
     + 0 comments
    mapfile -t array

output=$(grep -vi "a" <(printf "%s\n" "${array[@]}"))

if [ -z "$output" ]; then
 echo ""
else
 echo "$output"
fi

    The last part is horrible, but necessary for the challenge.

  • oriech90
     + 0 comments

    readarray -t array echo "${array[@]/*[aA]*/}" | xargs

    1. elements in the array that containing 'a' or 'A', will be replaced by ' '(space).
    2. xargs command trims leading and trailing spaces

    another approach: readarray -t array printf '%s\n' "${array[@]}" | grep -Ev "a|A"

    here printf prints each array element in a new line, The grep command here filters out 'a' or 'A'

  • locate_whoami
     + 1 comment

    arr=()

    while IFS= read -r line do if [[ "line") fi done

    echo "${arr[@]}"