Puzzle #5 was simple at first glance but required careful attention to details—exactly the kind of mental workout that's fun and useful. Looking forward to tomorrow’s! Gold365 Sign Up

Since the tables are in a circle, there are 10 adjacent pairs of seats that can be chosen, 2 ways to order the particular people in that pair and 8! ways to seat the remaining 8 people. There are 10! ways to seat the people without restrictions.

Suppose we want person A and person B to sit together. The only way that the 2 people sit together is if person B either sits to either the right or left of person A (& vice versa, considering one situation is enough) Person B has 9 seats to choose but can only sit next to Person A if they choose the 2 seats right next to them so its 2/9

can someone say what is wrong in this:

# Enter your code here. Read input from STDIN. Print output to STDOUT
from fractions import Fraction

table=['r','r']+['b' for i in range(8)]
table2 = list(table)
print(table)

count=0
total=0

for i in table:
    table2 = list(table)    
    table2.remove(i)
    for j in table2:
        table3 = list(table)    
        table3.remove(i)
        table3.remove(j)
        for k in table3:
            draw=i+j+k
            #print(draw)
            if any([m in draw for m in ['rrb','brr']]):
                print(draw,[m in draw for m in ['rrb','brr']])
                count+=1
            total+=1
            
print(Fraction(count, total))