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  1. Prepare
  2. Artificial Intelligence
  3. Probability & Statistics - Foundations
  4. Day 3: Basic Probability Puzzles #5
  5. Discussions

Day 3: Basic Probability Puzzles #5

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27 Discussions

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  • gschoen
     + 0 comments

    Since the tables are in a circle, there are 10 adjacent pairs of seats that can be chosen, 2 ways to order the particular people in that pair and 8! ways to seat the remaining 8 people. There are 10! ways to seat the people without restrictions.

  • sbhatta
     + 0 comments

    Suppose we want person A and person B to sit together. The only way that the 2 people sit together is if person B either sits to either the right or left of person A (& vice versa, considering one situation is enough) Person B has 9 seats to choose but can only sit next to Person A if they choose the 2 seats right next to them so its 2/9

  • kbgedia24
     + 0 comments

    can someone say what is wrong in this:

    # Enter your code here. Read input from STDIN. Print output to STDOUT
from fractions import Fraction

table=['r','r']+['b' for i in range(8)]
table2 = list(table)
print(table)

count=0
total=0

for i in table:
    table2 = list(table)    
    table2.remove(i)
    for j in table2:
        table3 = list(table)    
        table3.remove(i)
        table3.remove(j)
        for k in table3:
            draw=i+j+k
            #print(draw)
            if any([m in draw for m in ['rrb','brr']]):
                print(draw,[m in draw for m in ['rrb','brr']])
                count+=1
            total+=1
            
print(Fraction(count, total))

  • benorli_nathans1
     + 0 comments
    from fractions import Fraction
from math import comb

print(Fraction(10, comb(10, 2)))

  • phutvfx01501
     + 0 comments

    Python

    answer: 2/9

    from fractions import Fraction as F

tot = 0
tar = 0

for i in range(10):
    for j in range(10):
        if i != j:
            tot += 1
            if abs(i-j) == 1 or abs(i-j) == 9:
                tar += 1
print(F(tar,tot))