Sort by

recency

|

14 Discussions

|

  • + 0 comments

    A perfect reminder that in probability, how you count matters more than quick assumptions. Paddypower

  • + 0 comments

    Thanks for sharing this! You may also like https://nofalapparel.com/.

  • + 0 comments

    How to write the codes in Java? (Atleast first predefined lines) What language can we use?

    I am new to this platform. Please Help! Thank You.

  • + 0 comments

    One possible way to solve this is calculate all probabilities to get an interview: P(A)~P(B)~P(C) + ~P(A)P(B)~P(C) + ~P(A)*~P(B)*P(C) + P(A)P(B)~P(C)+ ... = Ans

    But: Ans + ~P(A)~P(B)~P(C) = 1 So, you just need to find 1 - ~P(A)~P(B)~P(C)

  • + 0 comments

    Why not just do 1 - P(Not getting into any company) = 1-(11/12 * 14/15 * 9/10) = 0.23 ?