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Thanks for this solution! I realized that
int i=min;i<=max;i++ iterates all the way to the highest value in b, which is unnecessary, as the largest possible factor of values in array b is the smallest value in it. Change int max = b[b.length-1]; to int max = b[0]; and you save a lot of unnecessary work.
The solution is very much helpful!!But "x" has to lie between the max value in array a and min value in arra y b.hence the values of min and max could be int min=a[a.length-1] and int max = b[0];This will reduce the time for processing the code.
Between Two Sets
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Thanks for this solution! I realized that
int i=min;i<=max;i++iterates all the way to the highest value in b, which is unnecessary, as the largest possible factor of values in array b is the smallest value in it. Changeint max = b[b.length-1];toint max = b[0];and you save a lot of unnecessary work.The solution is very much helpful!!But "x" has to lie between the max value in array a and min value in arra y b.hence the values of min and max could be int min=a[a.length-1] and int max = b[0];This will reduce the time for processing the code.
This is true just tested. So ideal range is
int min = a[a.length-1]; int max = b[0];:) :)