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  1. Practice
  2. Algorithms
  3. Implementation
  4. Between Two Sets
  5. Discussions

Between Two Sets

  • sumit371996 + 2 comments

    copy paste maar dia bhai

    • rajat_yadav + 1 comment

      aur kya kar sakta hai tu apni university ka naam hi dubaayega kuch seekh le in iit main padne walon se jo 50-50 lakh ka package kaise le jaate hain copy paste maarkar nahin kabhi hackerrank par unki profile check karna pata cjal jaayega

      • vivek4296 + 0 comments

        sahi bola, tera jaisa kahan hi h...yahan koi only u will get 50 lakh i know!!

    • rajat_yadav + 4 comments

      ye le solution samajh maine khudne banaya hai 2 ghante baith kar tu bhi bana saktaa hai agar hai himmat

      static int getTotalX(int[] a, int[] b) {
        int x=1,r=0,j=0,count=0;
        int[] d = new int[101];
        for(x=1;x<101;x++){
        	int c=0;
        		for(int i=0;i<a.length;i++) {
        			if(x%a[i]==0&&x>=a[i]){
        				c++;
        			}
        			}
        		if(c==a.length){
        			d[j]=x;
    				r++;
    				j++;
        		}
        		}
        for(j=0;j<r;j++){
        	int c=0;
            for(int i=0;i<b.length;i++){
         	   if(b[i]%d[j]==0){
         		   c++;
         	   }
            }
            if(c==b.length){
         	   count++;
            }
        }
        return count;
    }
      • shubhamchaudha11 + 0 comments

        Hi Rajat, can you please tell me about significance of "j"?

      • vivek4296 + 0 comments
        [deleted]
      • vivek4296 + 0 comments
        [deleted]
      • vivek4296 + 0 comments

        @rajat_yadav ye le.. tere wale se thoda easy hai

        static int gcd(int l,int e)
 {
     if(e==0)
     {
         return l;
     }
     else
     {
         return gcd(e,l%e);
     }
 }
 static int lcm(int[] e)
 {  
     int ans=1;
     for(int i:e)
     {
         ans=(ans*i)/gcd(ans,i);
     }
     return ans;
 }
static int getTotalX(int[] a, int[] b) {
    /*
     * Write your code here.
     */

     int count=0;
     int g=b[0];
     int l=lcm(a);
     for(int i=1;i<b.length;i++)
     {
         g=gcd(g,b[i]);
     }
     int m=l;
     int i=1;
     while(m<=g)
     {

         m=l*i;
         if(g%m==0)
         {
             count++;
         }
         i++;

     }

return count;

}