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with temp as (select distinct p,count(p) cnt from BST
group by p
having cnt>=2 )
select n,
case when p is null then "Root"
when n not in (select p from temp) then "Leaf"
else "Inner"
end as status
from BST
order by n
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Binary Tree Nodes
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with temp as (select distinct p,count(p) cnt from BST group by p having cnt>=2 ) select n, case when p is null then "Root" when n not in (select p from temp) then "Leaf" else "Inner" end as status from BST order by n